From 7e3b08871badb8328413a50b25ab58b84d5ab692 Mon Sep 17 00:00:00 2001 From: Rapptz Date: Mon, 8 Aug 2022 08:30:54 -0400 Subject: [PATCH] Fix documentation build failure from previous rename --- docs/faq.rst | 6 +++--- 1 file changed, 3 insertions(+), 3 deletions(-) diff --git a/docs/faq.rst b/docs/faq.rst index 7a37768e0..1369f4977 100644 --- a/docs/faq.rst +++ b/docs/faq.rst @@ -437,7 +437,7 @@ How can I disable all items on timeout? This requires three steps. -1. Attach a message to the :class:`~discord.ui.View` using either the return type of :meth:`~abc.Messageable.send` or retrieving it via :meth:`Interaction.original_message`. +1. Attach a message to the :class:`~discord.ui.View` using either the return type of :meth:`~abc.Messageable.send` or retrieving it via :meth:`Interaction.original_response`. 2. Inside :meth:`~ui.View.on_timeout`, loop over all items inside the view and mark them disabled. 3. Edit the message we retrieved in step 1 with the newly modified view. @@ -465,7 +465,7 @@ Putting it all together, we can do this in a text command: # Step 1 view.message = await ctx.send('Press me!', view=view) -Application commands do not return a message when you respond with :meth:`InteractionResponse.send_message`, therefore in order to reliably do this we should retrieve the message using :meth:`Interaction.original_message`. +Application commands do not return a message when you respond with :meth:`InteractionResponse.send_message`, therefore in order to reliably do this we should retrieve the message using :meth:`Interaction.original_response`. Putting it all together, using the previous view definition: @@ -478,7 +478,7 @@ Putting it all together, using the previous view definition: await interaction.response.send_message('Press me!', view=view) # Step 1 - view.message = await interaction.original_message() + view.message = await interaction.original_response() Application Commands